🤓 Based on our data, we think this question is relevant for Professor Tang's class at USF.

If the experiment below is run for 60 s, 0.16 mol A remain. Which of the following statements is or are true?

- After 60 s there are 0.84 mol B in the flask.
- The decrease in the number of moles of A from t
_{1}= 0 to t_{2}= 20 s is greater than that for t_{1}= 40 to t_{2}= 60 s. - The average rate for the reaction from t
_{1}= 40 to t_{2}= 60 s is 7.0 10^{-3}M/s.

Analyzing each statement, for Statement I: a

*fter 60 s there are 0.84 mol B in the flask*Checking the diagrams provided, each flask showed that

**s****um of mole A and B**, regardless of the time, will**always be 1**. Where at: 0s, moles A = 1 mol;

20s, moles A = 0.54 moles and moles B = 0.46 moles (0.54 + 0.46 = 1)

40s, moles A = 0.30 moles and moles B = 0.70 moles (0.30 + 0.70 = 1)

Therefore, at 60s if A is 0.16 moles, then B must be 0.84 moles (1 - 0.16 =

**0.84 moles**)

** Statement I is true**

Average Rate of Reaction

Average Rate of Reaction

Average Rate of Reaction

Average Rate of Reaction