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Solution: The proposed mechanism for the formation of hydrogen bromide can be written in a simplified form as:Br2(g)  ⇌ 2 Br(g)          Fast, k1 (forward), k–1 (reverse)Br(g) + H2(g) → HBr(g) + H(g)          Slow, k2H(g) + Br2(g) → HBr(g) +  Br(g)          Slow, k3What rate law corresponds to this mechanism?

Problem

The proposed mechanism for the formation of hydrogen bromide can be written in a simplified form as:
Br2(g)  ⇌ 2 Br(g)          Fast, k1 (forward), k–1 (reverse)
Br(g) + H2(g) → HBr(g) + H(g)          Slow, k2
H(g) + Br2(g) → HBr(g) +  Br(g)          Slow, k3

What rate law corresponds to this mechanism?