Problem: The easiest fusion reaction to initiate is21H + 31H → 42He + 10nCalculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.

FREE Expert Solution

To calculate the energy released:


21H + 31H → 42He + 10n


Step 1: mass defect (Δm)


m=products-reactants

m=mass He24+mass n01-mass H12+mass H13m=4.00260+1.00866 u             -2.01410 u+3.01605 um=5.01126 u-5.03015 amu

Δm = – 0.01889 u or amu


Convert to kg: 1 amu = 1.6606x10-27 kg

m=-0.01889 amu×1.6606×10-27 kg1 amu  

  Δm = – 3.1369 x10-29 kg

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Problem Details

The easiest fusion reaction to initiate is

21H + 31H → 42He + 10n

Calculate the energy released per  42He nucleus produced and per mole of  42He produced. The atomic masses are 21H, 2.01410 u; 31H, 3.01605 u; and 42He, 4.00260 u. The masses of the electron and neutron are 5.4858 X 10-4 u and 1.00866 u, respectively.




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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.