Problem: The most stable nucleus in terms of binding energy per nucleon is  56Fe. If the atomic mass of 56Fe is 55.9349 u, calculate the binding energy per nucleon for  56Fe.

🤓 Based on our data, we think this question is relevant for Professor Sharma's class at UM.

FREE Expert Solution

Step 1: Calculate the mass defect (Δm).

Given:

mass 56Fe = 55.9349 u

atomic # Ti = # of protons = 26

mass # = 56 

# of neutrons = 56 - 26 = 30


mass of proton = 1.007276 amu
mass neutron = 1.008665 amu



m=(neutrons+protons)-Fem=[30(1.008665 amu)+26(1.007276 amu)]-55.9349 amum=56.449126 amu-55.9349 amu

Δm = 0.514226 amu



Step 2: Calculate the mass defect (Δm) in kg.

1 amu = 1.6606x10-27 kg

m=0.514226 amu×1.6606×10-27 kg1 amu  

  Δm = 8.5392x10-28 kg



Step 3: Calculate the energy released (E).

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Problem Details

The most stable nucleus in terms of binding energy per nucleon is  56Fe. If the atomic mass of 56Fe is 55.9349 u, calculate the binding energy per nucleon for  56Fe.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Sharma's class at UM.

What textbook is this problem found in?

Our data indicates that this problem or a close variation was asked in Chemistry: An Atoms First Approach - Zumdahl 2nd Edition. You can also practice Chemistry: An Atoms First Approach - Zumdahl 2nd Edition practice problems.