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We’re being asked to determine the molarity of lead (Pb) in a 9.0-ppb solution. Let’s first define **ppm** and **ppb**.

• **1 ppm means 1 part of solute for every 10 ^{6} parts of the solution**

*in terms of solutions:*

$\overline{){\mathbf{p}}{\mathbf{p}}{\mathbf{m}}{\mathbf{=}}\frac{\mathbf{\mu}\mathbf{g}\mathbf{}\mathbf{s}\mathbf{o}\mathbf{l}\mathbf{u}\mathbf{t}\mathbf{e}}{\mathit{m}\mathit{L}\mathbf{}\mathbf{s}\mathbf{o}\mathbf{l}\mathbf{u}\mathbf{t}\mathbf{i}\mathbf{o}\mathbf{n}}}$

• **1 ppb means 1 part of solute for every 10 ^{9} parts of the solution**

The maximum allowable concentration of lead in drinking water is 9.0 ppb.

Calculate the molarity of lead in a 9.0- ppb solution.

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Based on our data, we think this problem is relevant for Professor Ghosh's class at GS.