Problem: The human body obtains ​950 kJ of energy from a candy bar.If this energy were used to vaporize water at 100.0 oC​, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)

FREE Expert Solution

We have to determine how many liters of water at 100 °C can be evaporated by absorption of 950 kJ of heat.


The amount of heat required for a substance to evaporate at its boiling point is given by this formula:

qvap = m·Hvap

Where,

qvap = amount of heat required for evaporation

m = mass of substance

ΔHvap = latent heat of vaporization

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Problem Details

The human body obtains 950 kJ of energy from a candy bar.

If this energy were used to vaporize water at 100.0 oC, how much water (in liters) could be vaporized? (Assume the density of water is 1.00 g/mL.)