Problem: Suppose that the spin quantum number, ms, could have three allowed values instead of two.What would be the number of elements in the second row of the periodic table?

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We are asked to determine the number of elements in the second row of the periodic table if the spin quantum number, ms, could have three allowed values instead of two.

Recall that the quantum numbers that define an electron are:

• Principal Quantum Number (n): deals with the size and energy of the atomic orbital. The possible values for n are 1 to ∞.

• Angular Momentum Quantum Number (l): deals with the shape of the atomic orbital. The possible values for l are 0 to n – 1.

• Magnetic Quantum Number (ml): deals with the orientation of the atomic orbital in 3D space. The possible values for ml are the range of –l to +l.

• Spin Quantum Number (ms): deals with the spin of the electron. The possible values for ms are either –1/2 (spin down) or +1/2 (spin up).


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Problem Details

Suppose that the spin quantum number, ms, could have three allowed values instead of two.

What would be the number of elements in the second row of the periodic table?

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