Ch.7 - Quantum MechanicsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: An electron confined to a one-dimensional box has energy levels given by the equation En = n2h2/8mL2, where n is a quantum number with possible values of 1, 2, 3, …, m is the mass of the particle, and L is the length of the box. Calculate the energies of the n = 1, n = 2, and n = 3 levels for an electron in a box with a length of 330 pm .

Solution: An electron confined to a one-dimensional box has energy levels given by the equation En = n2h2/8mL2, where n is a quantum number with possible values of 1, 2, 3, …, m is the mass of the particle, and

Problem

An electron confined to a one-dimensional box has energy levels given by the equation En = n2h2/8mL2, where n is a quantum number with possible values of 1, 2, 3, …, m is the mass of the particle, and L is the length of the box. Calculate the energies of the n = 1, n = 2, and n = 3 levels for an electron in a box with a length of 330 pm .