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Solution: The minerals hematite (Fe2O3) and magnetite (Fe3O4) exist in equilibrium with atmospheric oxygen: 4Fe3O4(s) + O2(g) ⇌ 6Fe2O3(s) Kp = 2.5 x 1087 at 298 K(a) Determine PO2 at equilibrium. 

Problem

The minerals hematite (Fe2O3) and magnetite (Fe3O4) exist in equilibrium with atmospheric oxygen: 

4Fe3O4(s) + O2(g) ⇌ 6Fe2O3(s) Kp = 2.5 x 1087 at 298 K

(a) Determine PO2 at equilibrium.