Chemistry Practice Problems Average Rate of Reaction Practice Problems Solution: The thiosulfate ion (S2O32-) is oxidized by iodine...

⚠️Our tutors found the solution shown to be helpful for the problem you're searching for. We don't have the exact solution yet.

Solution: The thiosulfate ion (S2O32-) is oxidized by iodine as follows:2S2O32- (aq) + I2 (aq) → S4O62- (aq) + 2I - (aq)In a certain experiment, 7.05 x 10-3 mol/L of S2O32- is consumed in the first 11.0 seconds of the reaction. Calculate the rate of consumption of S2O32-. Calculate the rate of production of iodide ion.

Problem

The thiosulfate ion (S2O32-) is oxidized by iodine as follows:

2S2O32- (aq) + I2 (aq) → S4O62- (aq) + 2I - (aq)

In a certain experiment, 7.05 x 10-3 mol/L of S2O32- is consumed in the first 11.0 seconds of the reaction. Calculate the rate of consumption of S2O32-. Calculate the rate of production of iodide ion.

Additional Practice Problems

Average Rate of Reaction

Average Rate of Reaction

Q. Consider the reaction: Cl2(g) + 3F2(g) → 2ClF3(g).Given that Δ[Cl2]/Δt = -0.054 M/s. Find Δ[F2]/Δt

Solved • Thu Dec 06 2018 09:35:11 GMT-0500 (EST)

Average Rate of Reaction

Q. Consider the reaction: Cl2(g) + 3F2(g) → 2ClF3(g).Given that Δ[Cl2]/t = -0.054 M/s. Find Δ[ClF3]/Δt

Solved • Thu Dec 06 2018 09:35:11 GMT-0500 (EST)