Ch.15 - Acid and Base EquilibriumWorksheetSee all chapters
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Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds

Solution: Calculate the concentration of each species present in a 0.010-M solution of phthalic acid, C6H4(CO2H)2.C6 H4(CO2 H)2(aq) + H2 O(l) ⇌ H3 O+(aq) + C6 H(CO2 H) (CO)(aq)        K a = 1.1 × 10−3 C6 H4(CO2 H)(CO2)(aq) + H2 O(l) ⇌ H3 O+(aq) + C6 H4(CO2)2−(aq)            K a = 3.9 × 10−6

Solution: Calculate the concentration of each species present in a 0.010-M solution of phthalic acid, C6H4(CO2H)2.C6 H4(CO2 H)2(aq) + H2 O(l) ⇌ H3 O+(aq) + C6 H4 (CO2 H) (CO2 )−(aq)        K a = 1.1 × 10−3C6 H4

Problem

Calculate the concentration of each species present in a 0.010-M solution of phthalic acid, C6H4(CO2H)2.

C6 H4(CO2 H)2(aq) + H2 O(l) ⇌ H3 O+(aq) + C6 H(CO2 H) (CO)(aq)        K a = 1.1 × 10−3
C6 H4(CO2 H)(CO2)(aq) + H2 O(l) ⇌ H3 O+(aq) + C6 H4(CO2)2−(aq)            K a = 3.9 × 10−6