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Setting up the Keq expression:
Keq = [products][reactants]50.2 = moles HI5 L21.25 mol I25 L1.25 mol H25 Lmoles HI5 L= (50.2)(0.25 mol I2)(0.25 mol H2)moles HI = (1.771)(5)
Calculate the number of moles of HI that are at equilibrium with 1.25 mol of H2 and 1.25 mol of I2 in a 5.00−L flask at 448°C.
H2 + I2 ⇌ 2HI K c = 50.2 at 448°C
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