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Solution: Nitrogen(II) oxide, NO, reacts with hydrogen, H2, according to the following equation: 2 NO + 2 H2 ⟶ N2 + 2H2O What would the rate law be if the mechanism for this reaction were: 2 NO + H2 ⟶ N2 + H2O2 (slow) H2O2 + H2 ⟶ 2H2O (fast)

Problem

Nitrogen(II) oxide, NO, reacts with hydrogen, H2, according to the following equation:
2 NO + 2 H2 ⟶ N2 + 2H2O

What would the rate law be if the mechanism for this reaction were:
2 NO + H2 ⟶ N2 + H2O2 (slow)
H2O2 + H2 ⟶ 2H2O (fast)