Problem: You may want to reference (Pages 397 - 400)Section 10.2 while completing this problem.What would be the height of the column in a barometer if the external pressure was 101 kPa and water (d = 1.00 g/cm3) was used in place of mercury?

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We are asked to determine the height of the column in a barometer if the external pressure was 101 kPa and water (d = 1.00 g/cm3was used in place of mercury.

Recall: 

The pressure can be calculated using the equation:

P=FA

The force, F, due to the air acting on the column is given by its mass times the acceleration due to gravity, 

F = mg

where g = 9.8 m/s2

The pressure caused by the air is:

P=FA=mgA

Recall that mass is related to density:

density=massvolume

We can treat the water as column whose volume equals its cross-sectional area times its height:

V=A×h

Hence, we have:

P=mgA=dVgA=d(Ah)gA=dhg

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Problem Details

You may want to reference (Pages 397 - 400)Section 10.2 while completing this problem.

What would be the height of the column in a barometer if the external pressure was 101 kPa and water (d = 1.00 g/cm3) was used in place of mercury?