Problem: A man homozygous for sickle cell disease (an autosomal recessive disease, i.e. not sex linked) who has normal vision marries a woman heterozygous for sickle cell disease who is colorblind (a recessive X-linked condition). What is the chance that a child (of either sex) born to them will have both sickle cell disease and be colorblind.A. 0B. 1/2C. 3/8D. 1/4E. 1/8

FREE Expert Solution

From the given problem, if we let A/a be the gene for sickle cell disease and the superscript b in the X chromosomes indicate the recessive colorblind allele, we can deduce that the man would have the genotype aaX+Y, while his wife would have the genotype AaXbXb.

View Complete Written Solution
Problem Details

A man homozygous for sickle cell disease (an autosomal recessive disease, i.e. not sex linked) who has normal vision marries a woman heterozygous for sickle cell disease who is colorblind (a recessive X-linked condition). What is the chance that a child (of either sex) born to them will have both sickle cell disease and be colorblind.

A. 0

B. 1/2

C. 3/8

D. 1/4

E. 1/8

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Chromosomal Theory of Inheritance concept. You can view video lessons to learn Chromosomal Theory of Inheritance. Or if you need more Chromosomal Theory of Inheritance practice, you can also practice Chromosomal Theory of Inheritance practice problems.