Problem: In swine, when a pure-breeding red is crossed to a pure-breeding white, the F1 are all red. However, the F2 shows 9/16 red, 1/16 white,and 6/16 are a new color, sandy. Thesandy phenotype is mots likely determined byA. complementary alleles of two different genes.B. a heterozygote of the alleles determines red and white.C. recessive epistasis.D. the presence of a dominant allele at either of two loci where red is determined by the dominant alleles of both loci.

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FREE Expert Solution

For this problem, having 16 possible outcomes suggests the involvement of 2 genes for color. And as shown by the F1 progeny, being a cross between two different true-breeding individuals, red is the dominant color. Thus, we let the genotype of the true-breeding red to be RRSS while the genotype of the true-breeding white is rrss. Their F1 progeny will all be dihybrids, RrSs.

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Problem Details

In swine, when a pure-breeding red is crossed to a pure-breeding white, the F1 are all red. However, the F2 shows 9/16 red, 1/16 white,and 6/16 are a new color, sandy. Thesandy phenotype is mots likely determined by

A. complementary alleles of two different genes.

B. a heterozygote of the alleles determines red and white.

C. recessive epistasis.

D. the presence of a dominant allele at either of two loci where red is determined by the dominant alleles of both loci.