Racoons have rings around their tails and a habit of washing their food in water before eating it.Suppose that both of these traits are controlled via incomplete dominance so that wide bands on the tail are BB, medium-sized bands are Bb and narrow bands are bb and that washing all food is WW, washing some food is Ww, and washing no food is ww. How many of each genotype will be in the F1 generation resulting from a cross of two raccoons that wash someof their food and have medium-sized tail bands? Assume each trait is on a different chromosome.
Suggestion - work the problem in the following order:
a. Write the parental cross
b. Use the fork-line method to determine the gametes produced by each parent.
c. Diagram a Punnet squate of this cross. Remember males go accross the top.
d. Determine the genotypic ratio (genotype along with how many) of the F1 offspring.
The mating is a dihybrid cross type, BbWw x BbWw
The gametes are BW, Bw, bW, and bw. They are the same for both parents
The Punnet square is shown below.